4q^2+16+16q=0

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Solution for 4q^2+16+16q=0 equation: 



4q^2+16+16q=0

a = 4; b = 16; c = +16;
Δ = b2-4ac
Δ = 162-4·4·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$q=\frac{-b}{2a}=\frac{-16}{8}=-2$

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